Question

A trolley, while going down an inclined plane, has an acceleration of 2 cm s .
What will be its velocity 3 s after the start?

Answer 1

Answer :-

0.06

Explanation :-

Given :

• Initial velocity, u = 0

• Acceleration,a = 2cms^-2 = 2/100 m/s^2 = 0.02m/s^2

• Time,t = 3s

To Find :

• Final velocity, v =?

Solution :

According to the first equation of motion,

$\boxed{\sf{}v=u+at}$

Put their values and solve it,

$\sf{}:\implies v=0+0.02m/s^2\times 3s$

$\sf{}\therefore 0.06m/s$

Therefore,final velocity of the trolly will be 0.06m/s.

☆Know more☆

Equations of Motion:

Relation among velocity, distance, time and acceleration is called equation of motion.

There are three equations of motion:

• 1st Equation of motion ( or Velocity-time relation): v = u + at

• 2nd Equation of motion ( or Position-time relation): s = ut + 1/2 at^2

• 3rd Equation of motion ( or Position-velocity relation): v^2 = u^2 +2as

Answer 2

Given :-

Acceleration of trolley, a = 2 cm/s² = 0.02 m/s²

Initial speed of trolley, u = 0 (As trolley starts from rest)

Time taken by trolley, t = 3 seconds

To Find :-

Final speed, v = ??

Formula to be used :-

1st equation of motion,

i.e, v = u + at

Solution :-

Putting all the values, we get

v = u + at

⇒ v = 0 + 0.02 × 3

⇒ v = 0.02 × 3

⇒ v = 0.06 m/s

Hence, the final velocity of trolley is 0.06 m/s.

Important Term :-

Final speed - Final speed is that speed which is acquired by the body after its start. It is denoted by v. When a body finally comes to rest, its final speed is zero.