a trolley while going down an inclined plane has an acceleration of 2 cm per second square what will be its velocity 3 seconds after the start
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a = 2 cm/s^2 ; t = 3 s ; u = 0 m/s
As v = u + a t
so, v = 0 + 2×3 cm/s
so, v = 6 cm/s
Hence the velocity will be 6 cm /s after 3s from the start.
As v = u + a t
so, v = 0 + 2×3 cm/s
so, v = 6 cm/s
Hence the velocity will be 6 cm /s after 3s from the start.
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➧ a ➾ 2 cm/s²
➧ u ➾ 0
➧ t ➾ 3 sec
➧ v ➾ ?
❱ So, v = u + at
v = 0 + (2 cm/s²) × (3 s)
v = 0 + 6 cm/s
v = 6 cm/s ...✔
_________ Thanks...✊
➧ a ➾ 2 cm/s²
➧ u ➾ 0
➧ t ➾ 3 sec
➧ v ➾ ?
❱ So, v = u + at
v = 0 + (2 cm/s²) × (3 s)
v = 0 + 6 cm/s
v = 6 cm/s ...✔
_________ Thanks...✊
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