Question

A trolley while going down and an inclined plane has an acceleration of 2 cm/s2 what will be its velocity 3 secs after the start

Answer 1

Given that, initial velocity of trolley = 0
acceleration =2cm/s^2
change into m/s^2
=0.02m/s^2
time taken, t = 3s
from 1st equation of motion
v=u+at
v=0+0.02*3
v=0.06m/s
hence the velocity of the trolley after 3s after start is 0.06m/s

Answer 2

Answer:

Solution,

Here, we have

Initial velocity of the trolley, u = 0 (As starts from rest)

Acceleration of the trolley, a = 0.02 m/s²

Time taken by the trolley, t = 3 seconds

To Find,

Final velocity of the trolley, v = ?

According to the 1st equation of motion,

We know that,

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ v = 0 + 0.02 × 3

⇒ v = 0.02 × 3

⇒ v = 0.06 m/s

Hence, the final velocity of the trolley is 0.06 m/s.