Question

a trolley whilexgoing down an inclined plan,has an acceleration of 2cm/s . What will be its velocity 3a after the start?​

Answer 1

Answer:

6

Explanation:

here i explain it

Given:

Given: Initial velocity is: u=0

Given: Initial velocity is: u=0Time is: t=3s

Given: Initial velocity is: u=0Time is: t=3sAcceleration is: a=2 cm s

Given: Initial velocity is: u=0Time is: t=3sAcceleration is: a=2 cm s −2

Given: Initial velocity is: u=0Time is: t=3sAcceleration is: a=2 cm s −2

Given: Initial velocity is: u=0Time is: t=3sAcceleration is: a=2 cm s −2 From first equation of motion:

Given: Initial velocity is: u=0Time is: t=3sAcceleration is: a=2 cm s −2 From first equation of motion: v=u+at

Given: Initial velocity is: u=0Time is: t=3sAcceleration is: a=2 cm s −2 From first equation of motion: v=u+atv=0+2×3=6 cm s

Given: Initial velocity is: u=0Time is: t=3sAcceleration is: a=2 cm s −2 From first equation of motion: v=u+atv=0+2×3=6 cm s −1

Answer 2

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INITIAL VELOCITY ( u ) = 0

TIME ( t ) = 3s

ACCELERATION ( a ) = 2cms^-2

FROM EQUATION - 1

v = u + at

v = 0 + 2 × 3

v = 6cms^-1