Question

A trolly of mass m=5kg is connected to a block of mass m=2kg with the help of massless inextensible spring passing over a light frictionless pulley as shown in the figure. Find the tension in the string

Answer 1

Answer:

Answer:

The tension in the string is 15.68 N.

Explanation:

Given that,

Mass of trolley = 5 kg

Mass of block = 2 kg

We need to calculate the tension in the string

According to FBD,

The tension is

f=mg sin cos theta

Where, m = mass of block

g = acceleration due to gravity

Put the value into the formula

T=5a....(1)

20sin53'–T = 2a... (2)

from 1&2..

20x 4/5=7a

a=16/7

& T=5a =› T=5x16/7

Hence, The tension in the string is 15.68 N.