Question

A truck attains a speed of 10 m s^-1 in 10 s starting from rest. Calculate the access of the truck. ​

Answer 1

Answer:

u=0

v=10m/s

t=10

a=v-u/t

a=10-0/10

a=1m/s^2

hope it will help u

Answer 2

Answer:

$\huge{\pink{\green {\sf\boxed{Acceleration = 1m {s}^{-1}}}}}$

Step-by-step explanation:

$\bold{\underline {Given:}}$

Initial velocity, ${</strong><strong>u</strong><strong> </strong><strong>=</strong><strong> </strong><strong>0</strong><strong> </strong><strong>m</strong><strong>}</strong><strong>{</strong><strong>s</strong><strong>}</strong><strong>^</strong><strong>{</strong><strong>-</strong><strong>1</strong><strong>}</strong><strong>$

Final velocity, ${</strong><strong>v</strong><strong> = </strong><strong>1</strong><strong>0 m}{s}^{-1}$

Time, ${</strong><strong>t</strong><strong> = </strong><strong>10s</strong><strong>}</strong><strong> </strong><strong>$

$\bold{\underline {</strong><strong>To</strong><strong> \:</strong><strong>Find</strong><strong>:</strong><strong>}</strong><strong>}</strong><strong>$

Acceleration, ${</strong><strong>a</strong><strong> </strong><strong>=</strong><strong> </strong><strong>?</strong><strong>}$

$\huge{\pink{\green {\sf\boxed{SOLUTION⟹}}}}$

Substituting the values in the equation ${</strong><strong>v</strong><strong> </strong><strong>=</strong><strong> </strong><strong>u</strong><strong> </strong><strong>+</strong><strong> </strong><strong>at</strong><strong>}$, we get

${</strong><strong>10</strong><strong> </strong><strong>=</strong><strong> </strong><strong>0</strong><strong> </strong><strong>+</strong><strong> </strong><strong>a</strong><strong> </strong><strong>×</strong><strong> </strong><strong>10</strong><strong>}$

$</strong><strong> </strong><strong>a</strong><strong> </strong><strong>=\d</strong><strong>frac</strong><strong>{</strong><strong>10</strong><strong>}</strong><strong>{</strong><strong>10</strong><strong>}</strong><strong>$

$\Large\boxed{a = \bf {1 m\:}{s}^{-1}}$

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