Question

A truck can carry 12 sacks of 100kg each at one time another truck can carry 15 sacks weighting 100 kgs each at one time if both trucks carry an equal number of bags in the day then what is the minimum number of sacks they could have carried

Answer 1

The minimum number of sacks they could have carried was 27.

Given, first truck can carry 12 sacks of 100kg each.

So, total weight carried by the truck = (12×100)kg = 1200kg at one time.

Again second truck can carry 15 sacks of 100kg each.

So, total weight carried = (15×100)kg = 1500kg at one time.

Total weight carried by the trucks = (!200+1500)kg = 2700kg

Let there be 'x' no. of sacks in both the trucks, each of whose weight is 100kg.

So, total weight of x no. of sacks = 100x kg.

We know, total weight carried by the trucks = 2700kg.

Thus, 100x = 2700

x = 2700/100 = 27

So, there are 27 sacks.