Question

A truck covers 40.0 m in 8.50 s while smoothly slowing

down to a final speed of 2.80 m/s. (a) Find its original

speed. (b) Find its acceleration.​

Answer 1

Answer:

the answer is too ask your mathes sir/mam

Answer 2

Answer:

(a) Here,

x

f

−x

i

=

2

1

(v

i

−v

f

)t becomes 40.0m=

2

1

(v

i

+280m/s)(8.50s)

Which yields v

i

=6.61m/s

(b) Similarly,

a=

t

v

f

−v

i

=

8.50s

2.80m/s−6.61m/s

=−0.448m/s

2

.