A truck driver is traveling from Sacramento to reno. After 1 hour the driver is 84 miles from reno. After two hours the driver is 36 miles from reno. Write the linear function that relates the time X in hours since leaving Sacramento to the drivers distance Y in miles from reno.
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Step-by-step explanation:
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Class 11
>>Physics
>>Motion in a Straight Line
>>Speed and Velocity
>>A driver of a car travelling at 52 km h^
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A driver of a car travelling at 52km h
−1
applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5s. Another driver going at 3km h
−1
in another car applies his brakes slowly and stops in 10s. On the same graph paper, plot the speed versus time graphs for the two cars. Which of the two cars travelled farther after the brakes were applied?
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Solution
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(A) : Initial speed of the car A u=52 kmh
−1
=52×
18
5
=14.44 ms
−1
The car stops in 5 seconds i.e v=0 at t=5
(A) : Initial speed of the car A u=3 kmh
−1
=3×
18
5
=0.83 ms
−1
The car stops in 10 seconds i.e v=0 at t=10
With the help of these initial and final points for both the cases, we can plot the graph of speed vs time.
Area under the speed-time graph gives the distance covered.
∴ Distance covered by car A x
A
=
2
1
×14.44×5=36.1 m
∴ Distance covered by car A x
B
=
2
1
×0.83×10=4.15 m
Thus car A travels more distance than B.
solution