Question

a truck driver slow down from 66km per hr to 30km per hr in 30 sec. find the retardation

Answer 1

Answer:given initial velocity that is u = 66 m/s and final velocity that is v = 30 m/s and time = 30 seconds

Explanation:convert km per ghr into m per sec 66kmper hr into m per sec 66 × 18 ÷5 = 227.6m /s and 30 km per sec into m per sec 30×18÷5= 108m /s

We know the first eq of motion a =v-u÷t

a =227.6-108÷30

a= 119.7÷30

a = -4m/sq