Question

A truck falls off a ledge and drops to the ground in 1 s. Calculate its speed on striking the ground and its

average speed during 1 s. [Take g = 10 m/s2

]​

Answer 1

Answer:

Explanation:

Given,

time taken=0.5s

g=10ms  

−2

 

As the car is under free fall, the initial speed is zero.

(a) Under free fall,  

u=0  

a=g

v=u+at

v=0+10×0.5

v=5ms  

−1

 

(b) Average speed =  

2

u+v

​  

=  

2

0+5

​  

=2.5ms  

−1

 

(c) From newton's equation of motion, As u=0,

h=ut+  

2

1

​  

gt  

2

 

When h is the height, t is the time of free fall, g is the acceleration due to gravity. Putting the values in the above equation, we get

h=  

2

1

​  

×10×(0.5)  

2

=5×0.25=1.25m

Answer 2

we know v=u+at

now,

u =0 as it falls

v=?

a=10m/s²

t=1s

now

v=0+10*1

v=10m/s

ii)avg v = v-u/total time

=10-0/1

=10m/s

Thx

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