a truck has a uniform acceleration motion of 8m/s square. what distance Will it cover in 30s after start?
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Given:
Initial velocity is: u=0
Acceleration is: a=4 ms
2
Time is: t=10 s
Using second equation of motion:
s=ut+
2
1
at
2
s=0×10+
2
1
×4×10
2
=0+200=200 m
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