A truck is moving at 15 m/s and has a Kinetic energy of 4.2 x 105 J. a)What is the mass of the truck? b)What multiplicative factor does the kinetic energy of truck increase if its speed is double.
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(I) the formula for kinetic energy =1/2mv^2
so we put
1/2mv^2 = 4.2 x10^5
m = 4.2x10^5 x 2/(15)^2
m= 840,000/225
m=3733.3 kg
so we put
1/2mv^2 = 4.2 x10^5
m = 4.2x10^5 x 2/(15)^2
m= 840,000/225
m=3733.3 kg
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