a truck is moving on a straight road with constant acceleration the initial velocityof car is 4m/s and after 10s its velocity becomes 16 m/ s calculate acceleration and distance in first 10s
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Answered by
15
a= (v-u)/t
a= (16-4)/10
a=12/10=1.2 m/s²
then
using second equation of motion
s=ut+1/2at²
s=4(10)+1/2×1.2×(10)²
s=40+1/2×120
s=40+60 =100 m
hope this helps
a= (16-4)/10
a=12/10=1.2 m/s²
then
using second equation of motion
s=ut+1/2at²
s=4(10)+1/2×1.2×(10)²
s=40+1/2×120
s=40+60 =100 m
hope this helps
Answered by
7
V = U + at
=> 16= 4+a10
=> 12=10 a
=> a=6/5
=> a=1.2m/sec
S = ut+1/2at²
=4(10) +1/2 (1.2)100
=100m
=> 16= 4+a10
=> 12=10 a
=> a=6/5
=> a=1.2m/sec
S = ut+1/2at²
=4(10) +1/2 (1.2)100
=100m
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