Question

A truck is moving wit the velocity of 72 km/hr. When the driver applies brakes, the truck is stopped in 2 seconds. Calculate the distance covered and retardation of the truck. If the mass of truck is 5000 kg, calculate the force applied by the brackets to stop the truck.

Answer 1

72x5/18=20m/s
U=20m/s
V=0m/s
T=2s
S=ut+ut^2
S=20x2+20x4
S=40+80
Distance =120km
A=v-u/t
A=0-20 /2
A=-10m/s2
F=mass x acceration
F=5000 x 10
F=50000