Question

A truck is moving with a constant velocity, u = 5m/s.
The driver stops for diesel and the truck accelerates
forward. After 20 seconds, the driver stops accelerating
to maintain a constant velocity, u = 25 m/s. What is
the truck's acceleration?​

Answer 1

Answer:

is -1/4 is the acceleration

Answer 2

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ᴀ ᴛʀᴜᴄᴋ ɪs ᴍᴏᴠɪɴɢ ᴡɪᴛʜ ᴀ ᴄᴏɴsᴛᴀɴᴛ ᴠᴇʟᴏᴄɪᴛʏ, ᴠ $\sf{=>5 m.s^{-1}}$. ᴛʜᴇ ᴅʀɪᴠᴇʀ sᴛᴏᴘs ғᴏʀ ᴅɪᴇsᴇʟ ᴀɴᴅ ᴛʜᴇ ᴛʀᴜᴄᴋ ᴀᴄᴄᴇʟᴇʀᴀᴛᴇs ғᴏʀᴡᴀʀᴅ. ᴀғᴛᴇʀ 20 sᴇᴄᴏɴᴅs, ᴛʜᴇ ᴅʀɪᴠᴇʀ sᴛᴏᴘs ᴀᴄᴄᴇʟᴇʀᴀᴛɪɴɢ ᴛᴏ ᴍᴀɪɴᴛᴀɪɴ ᴀ ᴄᴏɴsᴛᴀɴᴛ ᴠᴇʟᴏᴄɪᴛʏ, ᴠ $\sf{=>25 m.s^{-1}}$.ᴡʜᴀᴛ ɪs ᴛʜᴇ ᴛʀᴜᴄᴋ’s ᴀᴄᴄᴇʟᴇʀᴀᴛɪᴏɴ?

${\fbox{\fbox{\fbox{\huge\sf\purple{AnsWeR}}}}}$

Truck's acceleration is $\sf\frac{ 1 m}{s²}$

Explanation:

Given,

☞Initial velocity, (u)$\sf {=>5\frac{ m}{s}}$

☞Final velocity, (v) $\sf{=>25\frac{m}{s}}$

☞Time interval, (t) $\sf{=>20 \:s}$

From definition, acceleration is given as:

$\sf\star\green{a =>\frac{(v - u)}{t}}$

[ Putting values ]

$\sf\orange{↪a =>\frac{(25 - 5)}{20}}$

$\sf\red{↪a =>\frac{20}{20}}$

$\sf\blue{↪a = 1 m/s² }$

Equation of motion:

• v = u + at
• s = ut +$\frac{1}{2}$at²
• v² = u² + 2as