A truck is moving with a velocity of 36km/h.its accelerate 1.25m/s.calculate velocity and displacement after 5 sec
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Answered by
1
V= U+at
V=36*5/18+1.25*5...........(36km/hr has been converted to 10m/s)
=>V=16.25m/s
The velocity after 5 seconds=16.25m/s
S=V^2 - U^2/2a
=>S= (16.25)^2 - (10)^2/2*1.25
=>S=264.0625 - 100/2.5
=> S= 164.0625/2.5
=>S=65.625 meters
The displacement after 5 seconds = 65.625 meters
I hope this will help you
V=36*5/18+1.25*5...........(36km/hr has been converted to 10m/s)
=>V=16.25m/s
The velocity after 5 seconds=16.25m/s
S=V^2 - U^2/2a
=>S= (16.25)^2 - (10)^2/2*1.25
=>S=264.0625 - 100/2.5
=> S= 164.0625/2.5
=>S=65.625 meters
The displacement after 5 seconds = 65.625 meters
I hope this will help you
Answered by
0
V= U+at
V=36*5/18+1.25*5...........(36km/hr has been converted to 10m/s)
=>V=16.25m/s
The velocity after 5 seconds=16.25m/s
S=V^2 - U^2/2a
=>S= (16.25)^2 - (10)^2/2*1.25
=>S=264.0625 - 100/2.5
=> S= 164.0625/2.5
=>S=65.625 meters
The displacement after 5 seconds = 65.625 meters
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