Physics, asked by pinky182918, 11 months ago

A truck is moving with a velocity of 36km/h.its accelerate 1.25m/s.calculate velocity and displacement after 5 sec

Answers

Answered by beast14
1
V= U+at
V=36*5/18+1.25*5...........(36km/hr has been converted to 10m/s)
=>V=16.25m/s
The velocity after 5 seconds=16.25m/s

S=V^2 - U^2/2a
=>S= (16.25)^2 - (10)^2/2*1.25
=>S=264.0625 - 100/2.5
=> S= 164.0625/2.5
=>S=65.625 meters

The displacement after 5 seconds = 65.625 meters


I hope this will help you
Answered by SwapnilRao
0

V= U+at

V=36*5/18+1.25*5...........(36km/hr has been converted to 10m/s)

=>V=16.25m/s

The velocity after 5 seconds=16.25m/s

S=V^2 - U^2/2a

=>S= (16.25)^2 - (10)^2/2*1.25

=>S=264.0625 - 100/2.5

=> S= 164.0625/2.5

=>S=65.625 meters

The displacement after 5 seconds = 65.625 meters

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