Question

A truck is of mass 50000 kg. Its tyers exerts a pressure of 2500000 pa. The surface area of tyers in contact with the ground is..?

Answer 1

M = 50000 kg

P = 2500000 Pa

A =?

F = mg

F = 50000*10 = 500000

P = F / A

2500000 = 500000 / A

A = 500000 / 2500000

A = 0.2m^2


Thanks

Answer 2

Hey there!

Given,

Mass (m) = 50 000 kg

Pressure (P) = 2,500,000 pa

Force (F) = ?

Area (A) = ?

We know,

Force= Mass  * acceleration

         = 50 000 * 10

         = 5 00 000 N

And,

Pressure = Thrust / Area

Area = thrust / pressure

Area = 5,00,000 / 2500000

Area = 5/25

Area = 1/5 sq. unit

Hope It Helps You!