a truck is travelling at a speed 72km/h . it takes 3seconds to stopafterapplying brakes . find (1) acceleration of train and (2) the distance travelled by the train in 3s.
Answers
Answered by
1
Step-by-step explanation:
1) 72km/h=20m/s
So,
Acceleration = v-u ÷ t
a=20-0 ÷ 3
=20/3
a=6.666m/s^2
2)Distance = ut + 1/2at^2
d = (20×3) + (1/2×20/3×9)
d = 60+30
d = 90m
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Answered by
0
Answer:
u=72
v=0
t=3
therefore acceleration = v-u÷t
=0-72÷3
=-24 m per s square
distance traveled in 3 seconds =?
by 2 law of motion s =ut + 1÷2 at square
by solving the answer is 324
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