a truck mass 15 tonnes travelling at 1.6m/sec. impacts on a buffer spring which compresses 1.25 mm per KN. find the maximum compression of the spring
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Use conservation of energy
Kinetic energy of truck = 0.5mv^2
= 0.5 × 15 × 10^3 kg × (1.6 m/s)^2
= 19 200 joules
Energy stored in spring = 0.5kx^2
= 0.5 × (1.25 mm/kN) × x^2
= 6.25 × 10^-7 x^2 m/N
Equate both
19 200 = 6.25 × 10^-7 x^2
x = sqrt[(19 200) / (6.25 × 10^-7)]
x = 175.27 km
Maximum compression is spring is 175.27 km
Kinetic energy of truck = 0.5mv^2
= 0.5 × 15 × 10^3 kg × (1.6 m/s)^2
= 19 200 joules
Energy stored in spring = 0.5kx^2
= 0.5 × (1.25 mm/kN) × x^2
= 6.25 × 10^-7 x^2 m/N
Equate both
19 200 = 6.25 × 10^-7 x^2
x = sqrt[(19 200) / (6.25 × 10^-7)]
x = 175.27 km
Maximum compression is spring is 175.27 km
hitesh34:
will you please explain that energy stored in spring = 0.5kx^2
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Answer:219 mm
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