Question

A truck moves with the velocity of 36 km hr and gains speed to 72 km hr in 5 sec find the acceleration of the truck ​

Answer 1

Provided that:

• Initial velocity = 36 kmph
• Final velocity = 72 kmph
• Time = 5 seconds

To calculate:

• Acceleration

Solution:

• Acceleration = 2 m/s sq.

Using concepts:

• Formula to convert kmph-mps.

• To find the acceleration we ca use either acceleration formula or first equation of motion.

Using formulas:

• Formula to convert kmph-mps:

• ${\sf{1 \: kmph \: = \dfrac{5}{18} \: mps}}$

• Acceleration formula:

• ${\sf{a \: = \dfrac{v-u}{t}}}$

• First equation of motion:

• ${\sf{v \: = u \: + at}}$

Where, a denotes acceleration, v denotes final velocity, u denotes initial velocity and t denotes time taken.

Required solution:

~ Firstly let us convert initial velocity into metre per second!

$:\implies \sf 36 \times \dfrac{5}{18} \\ \\ :\implies \sf \cancel{36} \times \dfrac{5}{\cancel{{18}}} \\ \\ :\implies \sf 2 \times 5 \\ \\ :\implies \sf 10 \: ms^{-1} \\ \\ {\pmb{\sf{Henceforth, \: converted!}}}$

~ Now let us convert final velocity into metre per second!

$:\implies \sf 72 \times \dfrac{5}{18} \\ \\ :\implies \sf \cancel{72} \times \dfrac{5}{\cancel{{18}}} \\ \\ :\implies \sf 4 \times 5 \\ \\ :\implies \sf 20 \: ms^{-1} \\ \\ {\pmb{\sf{Henceforth, \: converted!}}}$

• Initial velocity = 10 mps
• Final velocity = 20 mps

~ Now calculating acceleration!

By using first equation of motion.

$:\implies \sf v \: = u \: + at \\ \\ :\implies \sf 20 \: = 10 + a(5) \\ \\ :\implies \sf 20 - 10 = 5a \\ \\ :\implies \sf 10 = 5a \\ \\ :\implies \sf \dfrac{10}{5} \: = a \\ \\ :\implies \sf 2 \: = a \\ \\ :\implies \sf a \: = 2 \: ms^{-2} \\ \\ :\implies \sf Acceleration \: = 2 \: ms^{-2}$

By using acceleration formula.

$:\implies \sf a \: = \dfrac{v-u}{t} \\ \\ :\implies \sf a \: = \dfrac{20-10}{5} \\ \\ :\implies \sf \dfrac{10}{5} \: = a \\ \\ :\implies \sf 2 \: = a \\ \\ :\implies \sf a \: = 2 \: ms^{-2} \\ \\ :\implies \sf Acceleration \: = 2 \: ms^{-2}$

Answer 2

Question:

• A truck moves with the velocity of 36 km hr and gains speed to 72 km hr in 5 sec find the acceleration of the truck ​

Answer:

• The acceleration of the truck is 2m/s²

Explanation:

Given that:

• A truck moves with the velocity of 36 kmph
• It  gains speed to 72 km hr in 5 seconds

To Find:

• The acceleration of the truck

Formulas Used:

$\bigstar \; {\underline{\boxed{\bf{ Acceleration =\dfrac{\triangle V}{\triangle T} }}}}$    

Required solution:

• Using first equation of motion

★ We Know that ,

${\pink{\bigstar \; {{\boxed{\bf{ v _{(final)} = v_{(initial)} + a_{(acceleration)}t_{(time \; period)} }}}}}}$

★ Where ,

• Velocity is considered as rate of change of position

• Acceleration is considered as the rate of change in velocity

• Time period is the progression of events from the past to the present into the future

★ Here we know that ,

• Initial velocity = 36 kmph
• Final velocity = 72 kmph
• Time period = 5 seconds

★ Converting the values into S.I System

$\star \; {\purple{\underline{\bf{ Initial \; velocity : }}}}$  

$\\\longrightarrow \rm Velocity_{(Initial)} = 36 km/h \\ \\ \\ \\ \longrightarrow \rm Velocity_{(Initial)} = 36 * \dfrac{5}{18} m/s \\ \\ \\ \\ \longrightarrow \rm Velocity_{(Initial)} = 2 * 5 m/s \\ \\ \\ \\ \longrightarrow \rm {\red{\underline{\underline{Velocity_{(Initial)} = 10m/s }}}}$

★ Henceforth ,

• The initial velocity of the object is 10m/s

$\star \; {\purple{\underline{\bf{ Final\; velocity : }}}}$

$\\\longrightarrow \rm Velocity_{(Finial)} = 72 km/h \\ \\ \\ \\ \longrightarrow \rm Velocity_{(Final)} = 72 * \dfrac{5}{18} m/s \\ \\ \\ \\ \longrightarrow \rm Velocity_{(Final)} = 4 * 5 m/s \\ \\ \\ \\ \longrightarrow \rm {\red{\underline{\underline{Velocity_{(Final)} = 20m/s }}}}$

★ Henceforth ,

• The final velocity of the object is 20m/s

According to the question:

• Since we have values of the initial velocity , the final velocity and the time taken by the object now let's use suitable equations of motion to find out the acceleration of the  object here to be considered as truck  

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★ we know that ,

${\pink{\bigstar \; {\underline{\boxed{\bf{ Acceleration =\dfrac{\triangle V}{\triangle T} }}}}}}$

$\star \; {\purple{\underline{\bf{ Finding \; Acceleration \; : }}}}$

$\\ \longrightarrow \rm Acceleration _{(of \; the \; truck)}= \dfrac{\triangle v}{\triangle t} \\ \\ \\ \\ \longrightarrow \rm Acceleration _{(of \; the \; truck)}= \dfrac{v_{(Final)}- v_{(Initial)}}{Time} \\ \\ \\ \\ \longrightarrow \rm Acceleration _{(of \; the \; truck)}=\dfrac{20m/s - 10m/s}{5\;s} \\ \\ \\ \longrightarrow \rm Acceleration _{(of \; the \; truck)}= \dfrac{10m/s}{5\;s} \\ \\ \\ \longrightarrow \rm{\red{\underline{\underline {Acceleration _{(of \; the \; truck)}= 2 m/s^2 }}}}$

★ Henceforth ,

• The acceleration of the truck is 2m/s²

Therefore:

• The acceleration of the truck is 2m/s²

Learn More from Brainly:

✧ Related Question ✧

• body starts from the rest , moves with a constant accerlation of 2 m/s 2 for 10 s the same body then later travels a distance of 20 m with a uniform velocity to reach its destianation calculate the total time taken to reach destination

✧ Answer ✧

• https://brainly.in/question/44474932

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