A truck moving with an initial velocity of 36 km h-1 accelerates uniformly at the rate of 10 cms-2 and covers a distance of 50 m. calculate 1) acceleration in
ms-2 ,2)velocity acquired in ms-1
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Step-by-step explanation:
u= 36km/hr = 10m/sec
a= 10cm/sec2 = 0.1 m/sec2
s= 50 m
i) acceleration in m/sec2 is 0.1
ii) velocity= 10m/sec
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