a truck moving with velocity of 90 km/h.the driver applies the brakes and the truck takes 5 second to stop .if the mass of the truck along with luggage is 1500kg then calculate the amount of fdorce exerted by the brakes on the truck
Answers
Answer:
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Explanation:
108 km/h and it takes 4 s to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcar if its mass along with the passengers is 1000 kg.
108 km/h and it takes 4 s to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcar if its mass along with the passengers is 1000 kg.Medium
Solution
verified
verifiedVerified by Toppr
verifiedVerified by TopprForce=mass*acceleration
verifiedVerified by TopprForce=mass*accelerationf=m×
verifiedVerified by TopprForce=mass*accelerationf=m× t
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000×
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 4
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 40−108×
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 40−108× 18
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 40−108× 185
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 40−108× 185
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 40−108× 185
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 40−108× 185
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 40−108× 185
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 40−108× 185 =1000×(−7.5)
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 40−108× 185 =1000×(−7.5)∴f=−7500N
verifiedVerified by TopprForce=mass*accelerationf=m× tv−u f=1000× 40−108× 185 =1000×(−7.5)∴f=−7500Nopposing force is denoted by negative sign.