Question

A truck of 1800 is moving with a speed of 54 km/hr when brakes are applied it stops with uniform negative acceleration at a distance of 200 m.calculate the force applied by the brakes and work done before stopping

Answer 1

Here's your answer
m=1800kg , u=54km/h=15m/s, v=0m/s, s=200m
v²-u²=2as, a= -225/2×200 =-0.56
Force= 1800×-0.56
=-1008N
Work done=-1008×200
=201600J
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