Physics, asked by stutikesharwani92, 2 months ago

A truck of 3000kg is moving with a velocity of 10m/sec. A force of 1000N acts on it in the forward direction due to the engine and a force of 400N acts in the backward direction due to friction: (1) with what rate it's velocity is increasing? (2) how much distance will it cover after 10sec?​

Answers

Answered by prajwalchaudhari
1

Answer:

force of 1000N acts on it in the forward direction due to the engine and a force of 400N acts in the backward direction due to friction:

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