a truck of mas 500000 kg is travelling at a speed of 20 m/s .it slowly comes to rest after travelling 60 m . find the required amount of force to bring the truck to rest.
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Here v=0 m/s and u= 40m/sK.E= ½ m u2=1/2x 5000x40 x40= 5000x20x40 = 4x 106JThus, when the truck is travelling with velocity of 40 m/s its kinetic energy is 4x 106J. while, when the truck comes to rest the kinetic energy of the truck becomes zero.
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5000 kg
5000 kg is the answer
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