Question

A truck of mass 10^3 kg travelling at 3m/s is brought to rest in 2 seconds when it strikes a buffer. What force is exerted by the buffer? please respond

Answer 1

Explanation:

u = 3 m/s

v = 0 m/s

t = 2 s

$a = \frac{v - u}{t} = \frac{0 - 3}{2} = - 1.5 \: m {s}^{ - 2}$

Here , the - sign indicates that the body is retarding.

$force = mass \times acceleration$

$= 1000 \times 1.5 = 1500 \: n$

The force exerted by the buffer is 1500 N.

I hope it helps you. If you have any doubts, then don't hesitate to ask.