a truck of mass 100 kg is moving at 20m/s is stopped by a force. find work done
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hey mate ur answer below
W=F.S
W=(100*9.8)*S
for distance=
u=20ms^-1
v=0
a=F/m
a=100*9.8/100
a=9.8ms^-2
using formula v^2-u^2=2as
S =400/19.6
s=20.4 m
hence,,, work = (100*9.8)20.4
980*20.4
w=1999.2 J
hope it helps!!!!!!!!!
W=F.S
W=(100*9.8)*S
for distance=
u=20ms^-1
v=0
a=F/m
a=100*9.8/100
a=9.8ms^-2
using formula v^2-u^2=2as
S =400/19.6
s=20.4 m
hence,,, work = (100*9.8)20.4
980*20.4
w=1999.2 J
hope it helps!!!!!!!!!
manavagarwal41p892r9:
Thanks guide
Guddu'
is the answer correct
wlcm
But your answer is wrong
BTW thanks for helping
I have edit
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