Question

a truck of mass 1000 kg accelerated from 36 km per hour to 72 km per hour in 20 second calculate the force applied by the engine of the truck

Anyone who answers it, I will make brainliest ​

Answer 1

Answer:-

Given:

Mass of the truck (m) = 1000 kg.

Initial Velocity of the truck (u) = 36 * 5/18 m/s = 10 m/s.

Final Velocity of the truck (v) = 72 * 5/18 m/s = 20 m/s.

Time taken (t) = 20 s.

We know that,

$\sf{Acceleration(a) = \frac{v - u}{t} } \\ \\ →\sf{Acceleration \: of \: the \: truck \: = \frac{20 - 10}{20} } \\ \\ → \sf{a = \frac{10}{20} } \\ \\ →\sf{Acceleration \: of \: the \: truck \: = 0.5 {ms}^{ - 2} }$

Now ,

Force applied = mass of the truck * acceleration

$→ \sf{F = 1000 \: kg \times 0.5 \: {ms}^{ - 2} } \\ \\ →\sf{F = 500 \: kg {ms}^{ - 2} } \\ \\ →\sf{F = 500 \: N}$

Hence, the force applied is 500 N.