A truck of mass 1000 kg, increases its speed from 36 kilometre per hour to 72
kilometre per hour. Calculate the increase in its kinetic energy.
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Answer:
first we have to convert km/hr to. m/s. So 36km/hr= 10m/s. 72km/hr= 20m/s
Explanation:
K.E1=1/2×m×v^2
=1/2×1000×10^2
=50000J
K.E2=1/2×m×v^2
=1/2×1000×20^2
=200000J
Increase in kinetic energy=K.E2 - K.E1
=200000J - 50000J
=150000J
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