a truck of mass 1000 kg , increases its speed from 36 km/h to 72km/h . find the increase in its kinetic energy
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i dont no.............
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Answer:
Mass of the truck(m) = 1000kg
Initial velocity(u) = 36km/h = 2m/s
Final velocity (v) = 72 km/h = 4m/s
Change in Kinetic energy = K.E(final) - K.E(initial)
=½mv²-½mu²
=½m(v²-u²)
=½×1000(4²-2²) = 500×(4+2)(4-2) = 500×6×2 = 500 × 12 = 6000J
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