Question

A truck of mass 2 x 10^4 kg travelling at 0.5 m/s collides
with another truck of half its mass moving in the opposite
direction with a velocity of 0.4 m/s. If the trucks couple
automatically on collision, calculate the common velocity
with which they move.​

Answer 1

Answer:

Explanation:Equate the both equation and find the value of 'V'......

I m trying my best .... Hope this will helpful

Answer 2

Answer:

• it's correct when we equate
• m1v1 + m2v2=m1v+m2v
• m1 mass of large truck with greater mass and m2 mass of small truck with half of the mass .
• so (2×10^4×0.5+10^4×0.4)=2×10^4×v+10^4v

Explanation:

• so ultimately we get
• 10^4(1+0.4)=10^4v(3)
• 1.4=3v
• v=1.4÷3=0.466=0.5(by rounding off)as 6is greater than 5 so +1 will be added to former digit 4 .