A truck of mass 2000 kg changes its velocity from 18km/hr to 36km/hr in 10sec calculate work done by the truck and power exerted.
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Answer:
Work done by the truck is 75 × 10³ Joule and power exerted is 7.5 watt.
Explanation:
Given:
mass, m = 2000kg
Initial velocity, u = 18 km/hr
Final velocity, v = 36 km/hr
time, t = 10 sec
To Find:
(i) Work done by the truck.
(ii) Power exerted by the truck.
Formulas Used:
Work done, w = ∆KE =
Power, P =
Solution:
(i) Work done by the truck = ?
Work done (w) = ∆KE =
w =
(ii) Power exerted by the truck = ?
Power (P) =
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