A truck of mass 2000 kg increases its speed from 54 km/hr to 72 km/hr. Its increase in kinetic energy will be
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Increase in kinetic energy is 5000 J.
Explanation:
Given :-
A truck of mass 2000 Kg increases its speed from 54 Km/hr to 72 Km/hr.
To find :-
Increase in kinetic energy.
Solution :-
Case (I) :
Mass (m) = 2000 Kg
Speed/Velocity (v₁) = 54 Km/hr
Velocity (v₁) = 54 × 5/18 = 15 m/s
Case (II) :
Mass (m) = 2000 Kg
Speed/Velocity (v₂) = 72 Km/hr
Velocity (v₂) = 72 × 5/18 = 20 m/s
Case (I) :
Kinetic energy = 1/2 mv₁²
K.E. = 1/2 × 2000 × 15
K.E. = 15000 J - (i)
Case (II) :
Kinetic energy = 1/2 mv₂²
K.E. = 1/2 × 2000 × 20
K.E. = 20000 J - (ii)
Increase in the kinetic energy will be :
(ii) - (i)
20000 J - 15000 J
5000 J
∴ Increase in kinetic energy is 5000 J.
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