A truck of mass 2500 kg moving at 15 m/s collides with a car of mass 1000 kg moving at 5 m/s in the opposite direction. With what velocity would the two move together?
Answers
Answer:
Explanation:
Let mass of truck=m1 and mass of car=m2
Total linear momentum before collision=m1u1+m2u2
=2500*25+1000*(-5)
=32500 kgm/s
Total momentum after collision=(m1+m2)V
=(2500+1000)V
On applying law of conservation of linear momentum
32500=3500*V
V=32500/3500=9.28m/sec
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Given:-
☆Mass of the truck(m1)=2500kg
☆Initial velocity of the truck(u1)=15m/s
☆Mass of the car=1000kg
☆Initial velocity of the car(u2)= -5m/s (as it is moving in opoosite direction)
To find:-
☆The velocity with which the two moves together after collision.
Solution:-
By law of conservation of momentum,we get:-
=>m1u1-m2u2=(m1+m2)v
=>2500×15-1000×5=(2500+1000)v
=>37500-5000=3500v
=>32500=3500v
=>v=32500/3500
=>v=9.28m/s
Thus,the both moves with a velocity of 9.28m/s after collision.