Question

A truck of mass 2500kg moving at 54km/hr collides with a car of mass 1000kg moving at 18 km/hr in the opposite direction. With what velocity and the direction would the two move together after collision?

Answer 1

$\bf{\underline{\underline\red{Given:-}}}$

• Mass of truck = 2500kg

• Velocity of truck = 54km/hr

• Mass of car = 1000kg

• Velocity of car = 18km/hr

$\bf{\underline{\underline\blue{To\:Find:-}}}$

• The velocity and the direction would the two move together after collision.

$\bf{\underline{\underline\green{Solution:-}}}$

Converting 54km/hr to m/s

$\rm \implies54 \times \dfrac{5}{18}$

$\rm \implies3 \times 5$

$\rm \implies15m/s$

∴ 54km/hr = 15m/s

Converting 18km/hr to m/s

$\rm \implies18\times \dfrac{5}{18}$

$\rm \implies1 \times 5$

$\rm \implies5m/s$

∴18km/h = 5m/s

Using the

Law of conservation of momentum.

Momentum before collision = Momentum after collision.

$\boxed{ \rm \implies m_{1} u_{1} + m_{2} u_{2} = ( m_{1} m_{2})v }$

Here:-

• $\rm m_{1} = mass \: of \: truck = 2500kg$

• $\rm u_{1} = velocity \: of \: truck = 15m/s$

• $\rm m_{2} = mass \: of \: car = 1000kg$

• $\rm u_{2} = velocity \: of \: car = 5m/s$

Substituting the values:-

$\rm \implies 2500 \times 15+ 1000 \times ( - 5)= ( 2500 + 1000)v$

Here, Velocity of car is negative because it is moving in the opposite direction with respect to the truck.

$\rm \implies 37500 - 5000= ( 3500)v$

$\rm \implies 32500= 3500v$

$\rm \implies \dfrac{32500}{3500}= v$

$\rm \implies \dfrac{325}{35}= v$

$\rm \implies \dfrac{65}{7}= v$

$\rm \implies 9.3= v$

Velocity = 9.3m/s

Direction = Direction in which the truck moves

Answer 2

☆☆ANSWER ☆☆

☆Hope this helps u a lot!!!☆

❤❤please mark me as a brainlist answer!!!!!!!❤❤