A truck of mass 3 tonnes moves up an incline at a constant velocity 10m/s against a frictional force 200 N. The incline is such that it rises 1m for every 15m along the incline. Calculate the power output of the truck engine.(g=10m/s)
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F= force applied by truck.
F= f+ mg sin theta
f= friction.
sin theta= 1/15.
Power=F*v
v=10m/sec
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