Question

a truck of mass 3000 kg initially at rest increases its velocity to 90 kilometre per hour in 0.5 minutes find the force developed. find the distance covered by the truck in 0.5 minute .​

Answer 1

Given:-

•Mass of the truck(m)=3000kg

•Initial velocity of the truck(u)=0

•Final velocity of the truck=90km/h

=>90×5/18

=>25m/s

•Time taken(t)=0.5 minute

=>30 seconds

To find:-

•Force(F)

•Distance covered by the truck(s)

Solution:-

By using the 1st equation of motion,we get:-

=>v=u+at

=>a=v-u/t

=>a=25-0/30

=>a= 5/6 m/s²

Thus,we have got acceleration of the truck as 5/6 m/s².

From Newton's 2nd law of motion,we get:-

=>F=ma

=>F=3000×5/6

=>F=2500N

Now,we shall use the 2nd equation of motion to find the distance covered:-

=>s=ut+1/2at²

=>s=0×30+1/2×5/6×(30)²

=>s=5/12×900

=>s=375m

Thus:-

•The force developed is 2500N

•Distance travelled by the truck in

0.5 minute is 375m.