Question

A truck of mass 3000kg is brought to rest from a speed 30m.S by a constant force 6000n how much time doest the truck take to come in rest

Answer 1

Mass of the truck = 3000 kg

Initial velocity (u) = 30 m/s

Initial momentum = 3000 × 30 = 90000 kg m/s

Final velocity (v) = 0 m/s

Final momentum = 3000 × 0 = 0

Change in momentum (p) = 90000 - 0 = 90000 kg m/s

Force = Rate of change of momentum

Let the time taken be t.

$force = \frac{p}{t}$

$t = \frac{p}{Force}$

$t = \frac{90000}{6000}$

t = 15 seconds

Hence, the time taken to stop the truck is 15 seconds.