Question

a truck of mass 5 ton travelling horizontally with 36 km per hour stops after 1 kilometre what friction its weight it is frictional force exerted by road? If we assume that the story repeats for car of mass 1 ton in similar distance same how much will the friction B ?​

Answer 1

The friction is $\dfrac{1}{200}$

Explanation:

Given that,

Mass of truck = 5 ton

Speed = 36 km/hr = 10 m/s

Distance = 1 km = 1000 m

We need to calculate the coefficient frictional

Using relation of frictional

$\mu mg=maμmg=ma</p><p></p><p>\mu=\dfrac{a}{g}μ=$

We need to calculate the fraction of its weight is the frictional force exerted by the road

Using formula of fraction

$\dfrac{F}{W}=\dfrac{\mu mg}{mg}$

$\dfrac{F}{W}=\mu$

$\dfrac{F}{W}=\dfrac{a}{g}$

Put the value of a from equation of motion

$\dfrac{F}{W}=\dfrac{\dfrac{v^2-u^2}{2s}}{g}$

Put the value into the formula

$\dfrac{F}{W}=\dfrac{100}{2\times10\times1000} </p><p></p><p> </p><p> </p><p>2×10×1000</p><p>100$

$\dfrac{F}{W}=\dfrac{1}{200} </p><p>W</p><p>F</p><p> </p><p> = </p><p>200</p><p>1$

If we assume that the story repeats for a car of mass 1 ton i.e., can moving with same speed stops in similar distance same

The fraction of its weight and the frictional force does not depend on the mass.

So, The fraction of its weight and the frictional force for car is same.

Hence, The friction is $\dfrac{1}{200}$

Answer 2

Answer:

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