Question

A truck of mass 500 kg accelerates from 10m/s to 20m/s by application of force for 5 seconds find work done

Answer 1

Answer:

Mass of the = 500kg.

Initial velocity of the = 10m/s.

Final velocity of the = 20m/s.

= 5s.

Therefore acceleration =(v-u) /t = (20-10/5)m/s^2 = 2m/s^2.

Therefore,

FORCE = MASS × ACCELERATION:

500kg × 2 m/s^2 = 1000N.

Now, 2as = v^2 - u^2.

or 2×2× s = 400 - 100.m

or s = 300/4m = 75m

Therefore Work done

= FORCE × DISPLACEMENT

= (1000 × 75) J = 75000J