Question

A truck of mass 5000 kg is moving with a velocity of 36 km per hour that applies the brakes in slow down the velocity of 18 kilometre our over a distance of 20 metre how much force is applied to slow down the track

Answer 1

Given:-

• Mass of the truck = 5000kg

• Initial Velocity of the truck = 36km/h = 10m/s

• Final Velocity = 18km/h = 5m/s

• Distance Covered = 20m.

To Find :-

• Force applied to slow down the track.

Formulae used:-

• v² - u² = 2as
• F = ma

Where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• s = Distance
• F = Force

Now,

→ v² - u² = 2as

→ (5)² - (18)² = 2 × a × 20

→ 25 - 324 = 40a

→ - 299 = 40a

→ a = -299/40

→ a = -7.4m/s²

Hence, The Retardation of truck is -7.4m/s²

Now again,

→ F = ma

→ F = 5000 × -7.4

→ F = 37,375N.

Hence, The Force applied brakes is 37,375N