Physics, asked by sibilsaren44, 2 months ago

a truck of mass 500kg , decreases its speed from 54km/h to 36km/h . find the decrease in its kinetic energy​

Answers

Answered by ramteja0712
0

Answer:

31250 J

Explanation:

36 kmph = 10 m/s

54 kmph = 15 m/s

Change in kinetic energy = 1/2 x 500 x (15^2-10^2)

Change in kinetic energy = 1/2 x 500 x (225-100)

Change in kinetic energy = 31250 J

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Answered by perfectico
0

Hey mate here is ur answer

❤❤

Explanation:

given :  \\ m = 500kg = 1000 \times 500g = 500000g \\ v1 = 54km {h}^{ - 1}  = 54 \times  \frac{5}{18}  = 15m {s}^{ - 1}  \\ v2 = 36km {h}^{ - 1}  = 36 \times  \frac{5}{18}  = 10m {s}^{ - 1}  \\initial \: kinetic \: energy   =  \frac{1}{2} m {(v1)}^{2} \\  =  \frac{1}{2}  \times 500000 \times 15 {}^{2}  \\  =  \frac{1}{2}  \times 500000 \times 225 \\  = 56250000 \: joule \\ final \: kinetic \: energy =  \frac{1}{2} m(v2) {}^{2}  \\  =  \frac{1}{2}  \times 500000 \times  {10}^{2}  \\  =  \frac{1}{2}  \times 500000 \times 100  \\ = 25000000 \: joule \\ decrease \: in \: kinetic \: energy = initial - final \\  = 56250000 - 25000000  \\ = 31,250,000 \: joule \: ans :

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