Question

a truck of mass 500kg , decreases its speed from 54km/h to 36km/h . find the decrease in its kinetic energy​

Answer 1

Answer:

31250 J

Explanation:

36 kmph = 10 m/s

54 kmph = 15 m/s

Change in kinetic energy = 1/2 x 500 x (15^2-10^2)

Change in kinetic energy = 1/2 x 500 x (225-100)

Change in kinetic energy = 31250 J

Please Mark Me Brainliest

For change in kinetic energy formula visit down photo

Answer 2

Hey mate here is ur answer

❤❤

Explanation:

$given : \\ m = 500kg = 1000 \times 500g = 500000g \\ v1 = 54km {h}^{ - 1} = 54 \times \frac{5}{18} = 15m {s}^{ - 1} \\ v2 = 36km {h}^{ - 1} = 36 \times \frac{5}{18} = 10m {s}^{ - 1} \\initial \: kinetic \: energy = \frac{1}{2} m {(v1)}^{2} \\ = \frac{1}{2} \times 500000 \times 15 {}^{2} \\ = \frac{1}{2} \times 500000 \times 225 \\ = 56250000 \: joule \\ final \: kinetic \: energy = \frac{1}{2} m(v2) {}^{2} \\ = \frac{1}{2} \times 500000 \times {10}^{2} \\ = \frac{1}{2} \times 500000 \times 100 \\ = 25000000 \: joule \\ decrease \: in \: kinetic \: energy = initial - final \\ = 56250000 - 25000000 \\ = 31,250,000 \: joule \: ans :$

Hope this helps

If yes thn plz mark it as BRAINLIEST!!

#thnq