A truck of mass 500Kg moving at 4 m/s collides with another truck of mass 1500 Kg moving in the same direction at 2m/s. What is their common velocity just after the collision if they move off together?
Answers
Answered by
360
by conservation of momentum,
mv = m1v1+m2v2
2000×v = 500×4 + 1500×2
2000v = 2000+3000
2000v = 5000
v = 5/2 = 2.5 m/s^2
so, after collosion their common velocity will be 2.5 m/s^2.
if it seems to be helpful mark me as brainliest.
mv = m1v1+m2v2
2000×v = 500×4 + 1500×2
2000v = 2000+3000
2000v = 5000
v = 5/2 = 2.5 m/s^2
so, after collosion their common velocity will be 2.5 m/s^2.
if it seems to be helpful mark me as brainliest.
IFTHI:
just one question how did u get mv = 200 x v
total mass of both truck is multiplied with velocity after collision which we have to find hope it helps
oh, thnx
hmm ur wlcm dear
Answered by
101
ANSWER
............
MV = M1V1 + M2V2
2000 * V = 500 * 4 + 1500 * 2
2000 V = 2000 + 3000
2000V = 5000
V = 5 / 2
MEANS THAT 2.5 M / S ^2
............
MV = M1V1 + M2V2
2000 * V = 500 * 4 + 1500 * 2
2000 V = 2000 + 3000
2000V = 5000
V = 5 / 2
MEANS THAT 2.5 M / S ^2
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