Question

A truck of mass M is moved under a force F. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved, then how does the acceleration change?

Answer 1

$\huge{\star}{\underline{\boxed{\red{\sf{Answer :}}}}}{\star}$

In First Case

Truck is with mass " m " and Force " F "

Then,

$\LARGE{\boxed{\boxed{\sf{F \: = \: ma}}}}$

$\Huge \implies {\boxed{\boxed{\sf{a \: = \: \frac{F}{m}}}}}$

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2nd case when mass is " 2m " and force is " F/2"

Now,

$\LARGE{\boxed{\boxed{\sf{F' \: = \: m' a'}}}}$

$\LARGE \implies {\boxed{\boxed{\sf{a' \: = \: \frac{\frac{F}{2}}{2m}}}}}$

$\Large{\boxed{\red{\sf{a' \: = \: (\frac{F}{4(m)}) }}}}$

∴ Acceleration will be 1/4 times