A truck of mass M is moved under a force F. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved, then how does the acceleration change?
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F=ma
According to the question, body of same mass is loaded.
Total Mass = m+m=2m
Force =
2
1
F
F=ma
⇒
2
1
F=2ma
∴a=
4m
F
So, acceleration becomes 1/4 times
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