A truck of mass M is moved under a force F. If the truck is than loaded with an
object equal to the mars of the truck and the driving force is halved (half),
than how does the acceleration change?
Answers
Answered by
2
Answer:
The original acceleration a=MF( F = ma)
Truck of mass M is loaded with a mass M and hence the total mass is 2M. Now, the driving force is also reduced to half.
Thus, M′=2M,F′=2F
Acceleration a′=2MF/2 or a′=41a
Acceleration becomes one-fourth of the original.
Explanation:
Answered by
0
F=ma
According to the question, body of same mass is loaded.
Total Mass = m+m=2m
Force =
2
1
F
F=ma
⇒
2
1
F=2ma
∴a=
4m
F
So, acceleration becomes 1/4 times
According to the question, body of same mass is loaded.
Total Mass = m+m=2m
Force =
2
1
F
F=ma
⇒
2
1
F=2ma
∴a=
4m
F
So, acceleration becomes 1/4 times
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