Physics, asked by manmohitgilluehshs, 7 months ago

A truck running at 90ℎ

−1

is brought to rest over a distance of 25m. Calculate the

acceleration and time for which brakes are applied.​

Answers

Answered by molakalabhoomika
1

Answer:

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Explanation:

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Answered by ParitoshGujrani
2

Answer:

Acceleration = - 12.5m/s^2

Time = 2 sec

Explanation:

u = 90 km/hr = 25 m/s

v = 0 m/s (since it is brought to rest)

s = 25 m

2as = v^2 - u^2

a = (v^2 - u^2) /2s

a = (0 - 625)/(2*25)

a = - 625/50

a = -12.5 m/s^2

a = (v-u) /t

t = (v-u) /a

t = (0-25)/-12.5

t = - 25/-12.5

t = 2 sec

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