Physics, asked by kanishka765, 8 hours ago

a truck running at 90 km/h slows down to 72 km/h over a distance of 10m. find the time taken and retardation​

Answers

Answered by MrsGoodGirl
0
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Answered by bsrsyamala
1

Answer:

0.44s,11.25m/s^2

Explanation:

u=90*5/18 m/s=25m/s

v=72*5/18=20m/s

S=10m

So now,

v^2-u^2=2aS

400-625=2a(10)

a=-225/20

Retardation=11.25m/s^2(as retardation is negative of acceleration)

Another,

v=u+at

20=25-(11.25)t

t=0.44s

Mark me as brainliest if you wish

Hope it helps

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