A truck start from rest and roll down a hill with constant acceleration. It travel a distance of 400m in 20s .find its acceleration. find the force acting on it if its Mass is 7metric tonnes.
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It is given that the truck start from rest and roll down a hill with constant acceleration, it means that the initial velocity of the truck is 0, as it was at the position of rest.
Therefore,
u = initial velocity = 0 m / s
We know,
Acceleration = ( v - u ) / ∆t , where v is the final velocity, u is the initial velocity and ∆t is the time taken.
Hence,
Acceleration = ( 400 - 0 ) / 20 m / s²
Acceleration = 400 / 20 m / s²
Acceleration = 20 m / s²
We know,
Force = Mass x acceleration
Force = 7000 kg x 20 m / s²
Force = 14000 N
Hence,
Acceleration is 20 m / s² and force applied by the truck is 14000 N
Therefore,
u = initial velocity = 0 m / s
We know,
Acceleration = ( v - u ) / ∆t , where v is the final velocity, u is the initial velocity and ∆t is the time taken.
Hence,
Acceleration = ( 400 - 0 ) / 20 m / s²
Acceleration = 400 / 20 m / s²
Acceleration = 20 m / s²
We know,
Force = Mass x acceleration
Force = 7000 kg x 20 m / s²
Force = 14000 N
Hence,
Acceleration is 20 m / s² and force applied by the truck is 14000 N
Answered by
2
Answer:
The truck starts from rest, so initial velocity = 0
Distance travelled = 400 m
Time taken = 20 s
We know the equation of motion, S = ut + ½ at2
400 = 0 + ½ a * (20)2 a = 2 m/s2
Now, mass = 7 metric tonnes = 7 * 1000 = 7000 kg
So force = mass * acceleration F = 7000 * 2 = 14000 N
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